https://github.com/0xadada/fizzbuzz.js

:honeybee: FizzBuzz solution for values n:m, w/optional divisors & text
https://github.com/0xadada/fizzbuzz.js

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:honeybee: FizzBuzz solution for values n:m, w/optional divisors & text

• Host: GitHub
• URL: https://github.com/0xadada/fizzbuzz.js
• Owner: 0xadada
• License: mit
• Created: 2015-11-14T22:15:15.000Z (almost 9 years ago)
• Default Branch: master
• Last Pushed: 2017-04-14T13:28:37.000Z (over 7 years ago)
• Last Synced: 2024-10-18T08:25:02.721Z (26 days ago)
• Language: JavaScript
• Homepage:
• Size: 3.91 KB
• Stars: 0
• Watchers: 3
• Forks: 0
• Open Issues: 0
• Metadata Files:
  • Readme: README.md
  • License: LICENSE

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README

        
# FizzBuzz.js

FizzBuzz solution for values n:m, w/optional divisors & text.

Return an array from values `n:m` for `i`, yielding `[f] + [b]` for value

`(n+i % div0) === 0 && (n+i % div1) === 0`, yielding `[f]` for value

`(n+i % div0) === 0`, yielding `[b]` for value `(n+i % div1) === 0`.

This solution to the FizzBuzz problem was inspired by a thread on Reddit

about common frontend developer interview questions. I [implemented a

solution using a bodyless for-loop with heavy use of ternary

operators](https://gist.github.com/0xadada/ccb5cd069138e5bb7549).

This example was then turned into this Node module for even more concise

code during an interview, where the developer can show his/her

pragmatism and reluctance for "reinventing the wheel".

## Usage

Simple usage:

    $ npm install -s fizzbuzz.js

Then:

    var fizzBuzz = require('fizzbuzz.js').fizzBuzz;

    var results = fizzBuzz();

FizzBuzz takes optional arguments:

* **n**: (Number) Start value, default: `1`

* **m**: (Number) End value, defalt: `100`

* **f**: (String) Alternative Fizz string, default `'Fizz'`

* **b**: (String) Alternative Buzz string, default `'Buzz'`

* **div0**: (Number) Alternative first divisible value, default `3`

* **div1**: (Number) Alternative second divisible value, default `5`

This will return an array for values 1 to 100, for values divisible by 3 and 5.

    var fizzBuzz = require('fizzbuzz.js').fizzBuzz;

    var results = fizzBuzz(1, 100, 'Fizz', 'Buzz', 3, 5);

Returns an array with the following indexed values:

    1 1

    2 2

    3 'Fizz'

    4 4

    5 'Buzz'

    6 'Fizz'

    7 7

    8 8

    9 'Fizz'

    10 'Buzz'

    11 11

    12 'Fizz'

    13 13

    14 14

    15 'FizzBuzz'

    16 16

    17 17

    18 'Fizz'

    19 19

    20 'Buzz'

    21 'Fizz'

    22 22

    23 23

    24 'Fizz'

    25 'Buzz'

    26 26

    27 'Fizz'

    28 28

    29 29

    30 'FizzBuzz'

    31 31

    32 32

    33 'Fizz'

    34 34

    35 'Buzz'

    36 'Fizz'

    37 37

    38 38

    39 'Fizz'

    40 'Buzz'

    41 41

    42 'Fizz'

    43 43

    44 44

    45 'FizzBuzz'

    46 46

    47 47

    48 'Fizz'

    49 49

    50 'Buzz'

    51 'Fizz'

    52 52

    53 53

    54 'Fizz'

    55 'Buzz'

    56 56

    57 'Fizz'

    58 58

    59 59

    60 'FizzBuzz'

    61 61

    62 62

    63 'Fizz'

    64 64

    65 'Buzz'

    66 'Fizz'

    67 67

    68 68

    69 'Fizz'

    70 'Buzz'

    71 71

    72 'Fizz'

    73 73

    74 74

    75 'FizzBuzz'

    76 76

    77 77

    78 'Fizz'

    79 79

    80 'Buzz'

    81 'Fizz'

    82 82

    83 83

    84 'Fizz'

    85 'Buzz'

    86 86

    87 'Fizz'

    88 88

    89 89

    90 'FizzBuzz'

    91 91

    92 92

    93 'Fizz'

    94 94

    95 'Buzz'

    96 'Fizz'

    97 97

    98 98

    99 'Fizz'

    100 'Buzz'

## Authors

*  [@0xadada](http://twitter.com/0xadada)

## License

MIT