https://github.com/azholtikov/zh_onewire

ESP32 ESP-IDF and ESP8266 RTOS SDK component for 1-Wire interface.
https://github.com/azholtikov/zh_onewire

component esp-idf esp32 esp8266 onewire rtos-sdk

Last synced: about 23 hours ago
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ESP32 ESP-IDF and ESP8266 RTOS SDK component for 1-Wire interface.

• Host: GitHub
• URL: https://github.com/azholtikov/zh_onewire
• Owner: aZholtikov
• License: apache-2.0
• Created: 2024-03-08T07:24:13.000Z (8 months ago)
• Default Branch: main
• Last Pushed: 2024-07-24T11:47:58.000Z (4 months ago)
• Last Synced: 2024-07-24T13:34:21.546Z (4 months ago)
• Topics: component, esp-idf, esp32, esp8266, onewire, rtos-sdk
• Language: C
• Homepage:
• Size: 9.77 KB
• Stars: 2
• Watchers: 1
• Forks: 0
• Open Issues: 0
• Metadata Files:
  • Readme: README.md
  • License: LICENSE

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README

        
# ESP32 ESP-IDF and ESP8266 RTOS SDK component for 1-Wire interface

## Tested on

1. ESP8266 RTOS_SDK v3.4

2. ESP32 ESP-IDF v5.2

## Using

In an existing project, run the following command to install the component:

```text

cd ../your_project/components

git clone https://github.com/aZholtikov/zh_onewire.git

```

In the application, add the component:

```c

#include "zh_onewire.h"

```

## Example

Search 1-Wire devices on bus:

```c

#include "zh_onewire.h"

void app_main(void)

{

    esp_log_level_set("zh_onewire", ESP_LOG_NONE);

    uint8_t *rom = NULL;

    zh_onewire_init(GPIO_NUM_5);

    if (zh_onewire_reset() != ESP_OK)

    {

        printf("There are no 1-Wire devices available on the bus.\n");

    }

    else

    {

        zh_onewire_search_rom_init();

        for (;;)

        {

            rom = zh_onewire_search_rom_next();

            if (rom == NULL)

            {

                break;

            }

            printf("Found device ROM: ");

            for (uint8_t i = 0; i < 8; ++i)

            {

                printf("%X ", *(rom++));

            }

            rom -= 8;

            printf("\n");

        }

    }

}

```

Any [feedback](mailto:[email protected]) will be gladly accepted.