https://github.com/dizzydroid/earth-day-quiz

A 15-Question Quiz for Earth Day 2023!
https://github.com/dizzydroid/earth-day-quiz

css3 html5 javascript open-source quiz webapp

Last synced: 11 months ago
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A 15-Question Quiz for Earth Day 2023!

• Host: GitHub
• URL: https://github.com/dizzydroid/earth-day-quiz
• Owner: dizzydroid
• Created: 2023-04-22T14:09:50.000Z (about 3 years ago)
• Default Branch: main
• Last Pushed: 2023-08-27T11:52:41.000Z (almost 3 years ago)
• Last Synced: 2025-01-17T18:32:44.232Z (over 1 year ago)
• Topics: css3, html5, javascript, open-source, quiz, webapp
• Language: JavaScript
• Homepage: https://dizzydroid.github.io/blog.html
• Size: 1.05 MB
• Stars: 1
• Watchers: 1
• Forks: 0
• Open Issues: 0
• Metadata Files:
  • Readme: README.md

Awesome Lists containing this project

README

          
# Earth Day Quiz 🌱️ 



 



## Celebrating Earth Day 2023 🌍️

### Can you ace this 15 - question quiz? Take it now and find out 😎️

#### The Quiz generates 15 random questions every time so you can test yourself over and over 🥸️

  

Take The Quiz! 



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#### Source Code is available in this repo, feel free to make your OWN quiz and share it with us 🤩️

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  Some Math 🔢 

  


Suppose you want to go over all the questions (50 questions), if you get ZERO questions repeated it would take you about 4 runs to complete it. But that's an extreme case, you will have questions repeated probably.. we could use a formula based on the expected number of runs for a given probability of repetition. This formula is derived from the Wald-Wolfowitz runs test, which is a statistical test for randomness in a sequence of binary outcomes. 

The formula is:

$$N = \frac{(1 - p)p}{\epsilon^2}(\Phi^{-1}(1 + \gamma/2))^2$$

where $N$ is the number of runs, $p$ is the probability of repetition, $\epsilon$ is the desired accuracy, $\gamma$ is the confidence level, and $\Phi^{-1}$ is the inverse cumulative distribution function of the standard normal distribution. 

For example, if you want to approximate the number of runs with 95% confidence and 5% accuracy, and you assume that each question has a 10% chance of being repeated, then the formula gives:

$$N = \frac{(0.9)(0.1)}{(0.05)^2}(\Phi^{-1}(0.975))^2 \approx 34.5$$

 So, you would need about 35 runs to cover all the questions with these assumptions.

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 This web-app is part of the DizzyBlog © dizzydroid. All rights reserved