Ecosyste.ms: Awesome

An open API service indexing awesome lists of open source software.
Awesome Lists | Featured Topics | Projects
https://github.com/gh0stkey/RGPerson

RGPerson - Randomly generate identity information
https://github.com/gh0stkey/RGPerson
python
Last synced: 23 days ago
JSON representation
RGPerson - Randomly generate identity information
Host: GitHub
URL: https://github.com/gh0stkey/RGPerson
Owner: gh0stkey
Created: 2019-08-13T09:02:11.000Z (over 5 years ago)
Default Branch: master
Last Pushed: 2021-08-19T10:49:23.000Z (over 3 years ago)
Last Synced: 2024-10-18T13:15:21.475Z (about 2 months ago)
Topics: python
Language: HTML
Homepage: https://gh0st.cn/RGPerson
Size: 110 KB
Stars: 482
Watchers: 8
Forks: 84
Open Issues: 0
Metadata Files:
- Readme: README.md
Awesome Lists containing this project

awesome-hacking-lists - gh0stkey/RGPerson - RGPerson - Randomly generate identity information (HTML)
README

        # RGPerson

项目地址：[https://github.com/gh0stkey/RGPerson](https://github.com/gh0stkey/RGPerson)

RGPerson - 随机身份生成

环境：python3

使用方法：python3 RGPerson.py

## 为什么需要Ta

相信很多师傅们在做测试的时候经常遇到一些注册的业务功能，要填写的东西很多，我一般都是临时去百度用的信息，这样很繁琐所以决定造轮子撸了个随机身份生成的。

## 介绍

该脚本生成信息：中国黑客ID\姓名\年龄\性别\身份证\手机号\组织机构代码\统一社会信用代码

## 脚本编写原理

**脚本的函数：** genMobile()、genIdCard()、genName()、genOrgCode()、genCreditCode()

genMobile() 为随机生成手机号的函数 

genName() 为随机生成姓名的函数

genIdCard() 为随机生成身份证的函数

genOrgCode() 为随机生成组织机构代码的函数

genCreditCode() 为随机生成统一社会信用代码的函数

### genMobile()

随机生成手机号：需要知道国内手机号的构成

1.长度为十一位

2.前三位表示运营商

现在我们只需要做到收集手机号号段的前三位以及对应的运营商：

```python

prelist = {"133":"电信","149":"电信","153":"电信","173":"电信","177":"电信","180":"电信","181":"电信","189":"电信","199":"电信","130":"联通","131":"联通","132":"联通","145":"联通","155":"联通","156":"联通","166":"联通","171":"联通","175":"联通","176":"联通","185":"联通","186":"联通","166":"联通","134":"移动","135":"移动","136":"移动","137":"移动","138":"移动","139":"移动","147":"移动","150":"移动","151":"移动","152":"移动","157":"移动","158":"移动","159":"移动","172":"移动","178":"移动","182":"移动","183":"移动","184":"移动","187":"移动","188":"移动","198":"移动"}

```

获取该数组的长度：len(prelist) -> 42

随机生成下标获取三位数：`prelist.keys()[random.randint(0,41)]`

然后再随机填补后8位即可：

```python

def genMobile():

    prelist = {"133":"电信","149":"电信","153":"电信","173":"电信","177":"电信","180":"电信","181":"电信","189":"电信","199":"电信","130":"联通","131":"联通","132":"联通","145":"联通","155":"联通","156":"联通","166":"联通","171":"联通","175":"联通","176":"联通","185":"联通","186":"联通","166":"联通","134":"移动","135":"移动","136":"移动","137":"移动","138":"移动","139":"移动","147":"移动","150":"移动","151":"移动","152":"移动","157":"移动","158":"移动","159":"移动","172":"移动","178":"移动","182":"移动","183":"移动","184":"移动","187":"移动","188":"移动","198":"移动"}

    three = list(prelist.keys())[random.randint(0,len(prelist)-1)]

    mobile = three + "".join(random.choice("0123456789") for i in range(8))

    op = prelist[three]

    return {mobile:op}

```

### genName()

随机生成姓名：中文名字通常为2、3位汉字组成

1.收集常用的姓氏随机取其一个：

```python

def first_name():

    first_name_list = ['赵', '钱', '孙', '李', '周', '吴', '郑', '王', '冯', '陈', '褚', '卫', '蒋', '沈', '韩', '杨', '朱', '秦', '尤', '许',

                '何', '吕', '施', '张', '孔', '曹', '严', '华', '金', '魏', '陶', '姜', '戚', '谢', '邹', '喻', '柏', '水', '窦', '章',

                '云', '苏', '潘', '葛', '奚', '范', '彭', '郎', '鲁', '韦', '昌', '马', '苗', '凤', '花', '方', '俞', '任', '袁', '柳',

                '酆', '鲍', '史', '唐', '费', '廉', '岑', '薛', '雷', '贺', '倪', '汤', '滕', '殷', '罗', '毕', '郝', '邬', '安', '常',

                '乐', '于', '时', '傅', '皮', '卞', '齐', '康', '伍', '余', '元', '卜', '顾', '孟', '平', '黄', '和', '穆', '萧', '尹',

                '姚', '邵', '堪', '汪', '祁', '毛', '禹', '狄', '米', '贝', '明', '臧', '计', '伏', '成', '戴', '谈', '宋', '茅', '庞',

                '熊', '纪', '舒', '屈', '项', '祝', '董', '梁']

    n = random.randint(0, len(first_name_list) - 1)

    f_name = first_name_list[n]

    return f_name

```

2.这里一开始想搜罗常用的名字，但参考了其他师傅的代码发现随机生成中文字符更好一点：

```python

def GBK2312():

    head = random.randint(0xb0, 0xf7)

    body = random.randint(0xa1, 0xf9)

    val = f'{head:x}{body:x}'

    st = bytes.fromhex(val).decode('gb2312')

    return st

```

3.随机生成名字的第二个字：(这里用一个list做一个空值，随机取生成的汉字或空值，**用于成为随机生成2位名字或3位名字**)

```python

def second_name():

    second_name_list = [GBK2312(), '']

    n = random.randint(0, 1)

    s_name = second_name_list[n]

    return s_name

```

4.随机生成名字的最后一个字：(用于满足三个汉字的名字)

```python

def last_name():

    return GBK2312()

```

5.拼接

```python

def last_name():

    return GBK2312()

```

### genIdCard()

随机生成身份证：公民身份号码是由17位数字码和1位校验码组成

18位数字组合的方式是：

| 1 1 0 1 0	2 | Y Y	Y Y	M M D D | 8 8         | 8           | X           |

| -------------- | --------------------- | ----------- | ----------- | ----------- |

| 区域码(6位)    | 出生日期码(8位)       | 顺序码(2位) | 性别码(1位) | 校验码(1位) |

- 6位区域码爬取http://www.360doc.com/content/12/1010/21/156610_240728293.shtml，存到了`districtcode.py`

> **区域码** 指的是公民常住户口所在县（市、镇、区）的[行政区划代码](https://zh.wikipedia.org/wiki/%E4%B8%AD%E5%8D%8E%E4%BA%BA%E6%B0%91%E5%85%B1%E5%92%8C%E5%9B%BD%E8%A1%8C%E6%94%BF%E5%8C%BA%E5%88%92%E4%BB%A3%E7%A0%81)，如110102是北京市-西城区。但港澳台地区居民的身份号码只精确到省级。

- 8位出生日期码，具体Python代码如下：

```python

age = random.randint(16,60) #可调整生成的年龄范围（身份证），这边是16-60岁

y = date.today().year - age #生成的年份

m = date(y, 1, 1) #生成的月份，初始值为1月1日

d = timedelta(days=random.randint(0, 364)) #随机生成的天数

datestring = str(m + d) #加天数得到最终值

```

> **出生日期码** 表示公民出生的公历年（4位）、月（2位）、日（2位）。

- 2位顺序码

> **顺序码** 表示在同一区域码所标识的区域范围内，对同年、同月、同日出生的人编定的顺序号。

- 1位性别码

> **性别码** 奇数表示男性，偶数表示女性。

- 最后一位是**校验码**，这里采用的是**ISO 7064:1983,MOD 11-2**校验码系统。校验码为一位数，但如果最后采用校验码系统计算的校验码是“10”，碍于身份证号码为18位的规定，则以“X”代替校验码“10”。

最难的还是校验码的算法，参考师傅的解说：

>1.将前面的身份证号码17位数分别乘以不同的系数。从第一位到第十七位的系数分别为：7 9 10 5 8 4 2 1 6 3 7 9 10 5 8 4 2 

>2.将这17位数字和系数相乘的结果相加。 

>3.用加出来和除以11，得余数

>4.余数只可能是0 1 2 3 4 5 6 7 8 9 10这11个数字，其分别对应的最后一位身份证的号码为1 0 X 9 8 7 6 5 4 3 2。 

>5.通过上面得知如果余数是2，就会在身份证的第18位数字上出现罗马数字的Ⅹ，如果余数是10，身份证的最后一位号码就是2。 

测试代码如下，取了几个真实的身份证号码发现可用：

```python

def test(id_num):

	id_code_list = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2]

	check_code_list = [1, 0, 'X', 9, 8, 7, 6, 5, 4, 3, 2]

	a = 0

	print(len(id_num))

	for i in range(17):

		a = a + (int(id_num[i]) * id_code_list[int(i)])

	print(check_code_list[a % 11])

```

整合一下（Copy）就变成了如下完整的代码：

```python

def genIdCard(age,gender):

    area_code = ('%s' % random.choice(list(area_dict.keys())))

    id_code_list = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2]

    check_code_list = [1, 0, 'X', 9, 8, 7, 6, 5, 4, 3, 2]

    if str(area_code) not in area_dict.keys():

        return None

    datestring = str(date(date.today().year - age, 1, 1) + timedelta(days=random.randint(0, 364))).replace("-", "")

    rd = random.randint(0, 999)

    if gender == 0:

        gender_num = rd if rd % 2 == 0 else rd + 1

    else:

        gender_num = rd if rd % 2 == 1 else rd - 1

    result = str(area_code) + datestring + str(gender_num).zfill(3)

    b = result + str(check_code_list[sum([a * b for a, b in zip(id_code_list, [int(a) for a in result])]) % 11])

    return b

```

## 参考

https://www.cnblogs.com/evening/archive/2012/04/19/2457440.html

https://www.cnblogs.com/thunderLL/p/7682148.html

https://blog.csdn.net/ak739105231/article/details/83932151

https://github.com/jayknoxqu/id-number-util

https://blog.csdn.net/tobacco5648/article/details/50613025

https://github.com/xbeginagain/generator