https://github.com/hansemannn/iOS11-PasswordFill-Example

Example showing how to use the PasswordFill API in iOS 11.
https://github.com/hansemannn/iOS11-PasswordFill-Example

example ios11 passwordfill

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Example showing how to use the PasswordFill API in iOS 11.

• Host: GitHub
• URL: https://github.com/hansemannn/iOS11-PasswordFill-Example
• Owner: hansemannn
• Created: 2017-07-04T04:20:16.000Z (over 7 years ago)
• Default Branch: master
• Last Pushed: 2019-01-18T14:03:36.000Z (almost 6 years ago)
• Last Synced: 2024-05-01T20:22:51.208Z (7 months ago)
• Topics: example, ios11, passwordfill
• Language: Swift
• Size: 20.5 KB
• Stars: 5
• Watchers: 1
• Forks: 3
• Open Issues: 0
• Metadata Files:
  • Readme: README.md

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README

        
# 🔑 iOS 11 PasswordFill Example

A quick example showing how to use the PasswordFill API in iOS 11 and Swift 4.

## Prerequisites

* Xcode 9+

* "Associated Domains" capability added to your project's `.entitlements` file (when using own domains)

```xml

com.apple.developer.associated-domains

  webcredentials:your-domain.com

```

## Getting Started

In order to make the PasswordFill API work, you need to set the `textContentType` property of

your `UITextField` or `UITextView` to `.username` and `.password`:

```swift

let textField = UITextField(frame: CGRect(x: 20, y: 30, width: 300, height: 40))

textField.backgroundColor = UIColor.lightGray

textField.textContentType = .username

textField.placeholder = "Enter Username ..."

let textField2 = UITextField(frame: CGRect(x: 20, y: 70, width: 300, height: 40))

textField2.backgroundColor = UIColor.lightGray

textField2.textContentType = .password

textField2.placeholder = "Enter Password ..."

textField2.isSecureTextEntry = true

```

Then, create a file called `apple-app-site-association` with the following contents:

```json

{

    "webcredentials" : {

        "apps" : ["."]

    }

}

```

Finally, upload the file to your server and place it into the sub-directory `.well-known`.

That's it!

## Author

Hans Knöchel ([@hansemannnn](https://twitter.com/hansemannnn))