https://github.com/iomarmochtar/ozpy

Python library for accessing Zimbra SOAP.
https://github.com/iomarmochtar/ozpy

api python-library zimbra

Last synced: 1 day ago
JSON representation

Python library for accessing Zimbra SOAP.

• Host: GitHub
• URL: https://github.com/iomarmochtar/ozpy
• Owner: iomarmochtar
• License: gpl-2.0
• Created: 2017-06-12T06:11:06.000Z (over 7 years ago)
• Default Branch: master
• Last Pushed: 2021-03-16T03:18:53.000Z (over 3 years ago)
• Last Synced: 2024-10-03T02:14:45.044Z (about 1 month ago)
• Topics: api, python-library, zimbra
• Language: Python
• Size: 25.4 KB
• Stars: 4
• Watchers: 1
• Forks: 5
• Open Issues: 2
• Metadata Files:
  • Readme: README.rst
  • License: LICENSE

Awesome Lists containing this project

README

        
OZPY

====

Python (2.7+ including 3.X) library for accessing Zimbra SOAP (https://wiki.zimbra.com/wiki/SOAP_API_Reference_Material_Beginning_with_ZCS_8) by using builtin Python library (no dependency required).

Currently this library split into 2 parts: Zmprov and Mailbox.

not all zmprov command(s) has been implemented, because i add them only based on customer/project needs

but you can add your own by extending **OZSoap** which is base of **Zmprov** and **Mailbox**

for example creating new COS (Class Of Service)

.. code-block:: python

	from ozpy.base import OZSoap

	class NewClass(OZSoap):

		def create_cos(self, name):

			body = {"name": [{

			  "_content": name

			}]}

			return self.send("CreateCos", body)

or directly call the soap method (by omitting Request suffix)

.. code-block:: python

	# zmsoap_obj is an instance from class OZSoap

	zmsoap_obj.CreateCos(

		name=[{"_content": "barudong"}]

	)

you can use **zmsoap** to get the parameters in soap body by using **--verbose** and **--json**

.. code-block:: bash

	zmsoap -z CreateCosRequest/name=new_cos  --json --verbose

Examples

--------

fetch all account

.. code-block:: python

	from ozpy.zmprov import Zmprov

	zmprov = Zmprov(

		username="[email protected]",

		password="superpassword",

		soapurl="https://192.168.113.75:7071/service/admin/soap"

	)

	print( zmprov.gaa() )

Sending email

.. code-block:: python

	from ozpy.mailbox import Mailbox

	mbx = Mailbox(

		username="[email protected]",

		password="superpassword",

		soapurl="https://192.168.113.75/service/soap"

	)

	mbx.sendMail('[email protected]', 'This is subject', 'Email content')