https://github.com/jumperbot/split-every

Split for every n occurrences of a pattern iteratively!
https://github.com/jumperbot/split-every

rust rust-crate rust-lang rust-language rust-library split splitter splitting splitting-text string string-formatting string-manipulation text

Last synced: 3 months ago
JSON representation

Split for every n occurrences of a pattern iteratively!

• Host: GitHub
• URL: https://github.com/jumperbot/split-every
• Owner: JumperBot
• License: mit
• Created: 2024-08-07T03:58:54.000Z (11 months ago)
• Default Branch: master
• Last Pushed: 2024-12-21T13:43:29.000Z (7 months ago)
• Last Synced: 2025-04-06T07:17:23.250Z (3 months ago)
• Topics: rust, rust-crate, rust-lang, rust-language, rust-library, split, splitter, splitting, splitting-text, string, string-formatting, string-manipulation, text
• Language: Rust
• Homepage: https://crates.io/crates/split-every
• Size: 9.77 KB
• Stars: 1
• Watchers: 1
• Forks: 0
• Open Issues: 0
• Metadata Files:
  • Readme: README.md
  • License: LICENSE

Awesome Lists containing this project

README

        


# split-every

![crates.io version](https://img.shields.io/crates/v/split-every.svg?label=release)

![github.com forks](https://img.shields.io/github/forks/JumperBot/split-every)

![github.com stars](https://img.shields.io/github/stars/JumperBot/split-every)

![crates.io downloads](https://img.shields.io/crates/d/split-every.svg?label=downloads)



---

```rust

use split_every::prelude::*;

// This prints: [(0, 0), (0, 1)]

//              [(0, 0)]

//              [(0, 1), (0, 0)]

//              [(0, 1)]

let mut splitter: SplitEvery<&[(u8, u8)], &[(u8, u8)]> = [

    (0, 0), (0, 1), (0, 0),

    (0, 0), (0, 0), (0, 1),

    (0, 0), (0, 0), (0, 1),

].split_every_n_times(&[(0, 0)], 2);

println!("{:?}", splitter.next().unwrap());

println!("{:?}", splitter.next().unwrap());

println!("{:?}", splitter.next().unwrap());

println!("{:?}", splitter.next().unwrap());

// This prints: "Oh hi there"

//              "I don't really"

//              "know what to"

//              "say".

let mut splitter: SplitEvery<&str, &str> =

    "Oh hi there I don't really know what to say".split_every_n_times(" ", 3);

println!("{:?}", splitter.next().unwrap());

println!("{:?}", splitter.next().unwrap());

println!("{:?}", splitter.next().unwrap());

println!("{:?}", splitter.next().unwrap());

// This prints: ["This", "is", "you", "This"]

//              ["me", "This", "is", "someone", "This"]

//              ["them"]

let mut splitter: SplitEvery Option<&'static str>>, &str> = [

    ["This", "is", "you"],

    ["This", "is", "me"],

    ["This", "is", "someone"],

    ["This", "is", "them"],

]

.iter()

.flatten()

.copied()

.split_every_n_times("is", 2);

println!("{:?}", splitter.next().unwrap());

println!("{:?}", splitter.next().unwrap());

println!("{:?}", splitter.next().unwrap());

// This prints: ["This", "is", "you", "This"]

//              ["me", "This", "is", "someone", "This"]

//              ["them"]

let mut iter = [

    ["This", "is", "you"],

    ["This", "is", "me"],

    ["This", "is", "someone"],

    ["This", "is", "them"],

].iter().flatten().map(|val| *val);

let mut splitter: SplitEvery Option<&'static str>>, &str> =

    SplitEvery::n_times_from_fn(Box::new(move || iter.next()), "is", 2);

println!("{:?}", splitter.next().unwrap());

println!("{:?}", splitter.next().unwrap());

println!("{:?}", splitter.next().unwrap());

```

---

## ✨ Split For Every N Occurrences Of A Pattern Iteratively

This crate **helps you** split data for every `n` occurrences of a `pattern`.  

It contains an exclusive `iterator`.

---

## 📄 Licensing

`split-every` is licensed under the [`MIT LICENSE`](./LICENSE); This is the [`summarization`](https://choosealicense.com/licenses/mit/).