https://github.com/jxm262/2048-scala

2048 implementation in Scala
https://github.com/jxm262/2048-scala

Last synced: 19 days ago
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2048 implementation in Scala

• Host: GitHub
• URL: https://github.com/jxm262/2048-scala
• Owner: jxm262
• License: apache-2.0
• Created: 2014-07-09T17:50:17.000Z (over 10 years ago)
• Default Branch: master
• Last Pushed: 2014-12-16T18:41:00.000Z (almost 10 years ago)
• Last Synced: 2023-08-21T11:26:03.847Z (about 1 year ago)
• Language: Scala
• Size: 742 KB
• Stars: 1
• Watchers: 3
• Forks: 0
• Open Issues: 0
• Metadata Files:
  • Readme: README.md
  • License: LICENSE

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README

        
2048 implemented in Scala

=========================

I've added 3 levels of difficulty to the original 2048 game (easy | medium | hard)

## Try it out here!  

http://jmaat.me/2048-Scala

  

Please note, this is NOT a good example of scala code :)  Just something I was playing around with while on an airplane ride back from a conference in Denver.  I tweaked it a bunch, but it's most likely missing a bunch of unit tests, could use refactoring, etc..  

The basic idea is to make a call to a REST service which calculates the entire game board in 1 step.  

For example 

a grid board like -

 1, 2, 3, 4  

 1, 2, 7, 8  

 9, 7, 4, 5  

 8, 5, 4, 3

Move up, will call the service as -  

[POST] 2048-Scala/move  

data:  {  

  direction: "up",  

  nums: [1,2,3,4,1,2,7,8,9,7,4,5,8,5,4,3]

  mode: "easy"  

}  

And return the resulting list after transposing and summing any matching sibling cell (on upwards motion), then insert a random 2 in an open spot. 

returns  

[2,4,3,4,,9,7,7,8,8,5,8,5,0,2,0,3]

And I use Jquery to reset the board -   

 2, 4, 3, 4  

 9, 7, 7, 8  

 8, 5, 8, 5  

 0, 2, 0, 3