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https://github.com/kuzmoyev/beautiful-date

Simple and beautiful way to create date and datetime objects in Python.
https://github.com/kuzmoyev/beautiful-date

beautiful date date-range python simple timedelta

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Simple and beautiful way to create date and datetime objects in Python.

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# Beautiful Date

[![PyPI version](https://badge.fury.io/py/beautiful-date.svg)](https://badge.fury.io/py/beautiful-date)
[![Tests](https://github.com/kuzmoyev/beautiful-date/workflows/Tests/badge.svg)](https://github.com/kuzmoyev/beautiful-date/actions)
[![Downloads](https://pepy.tech/badge/beautiful-date)](https://pepy.tech/project/beautiful-date)

Simple and beautiful way to create date and datetime objects in Python.

**Before**:

```python3
from datetime import date, datetime

d = date(year=2018, month=3, day=25)
t = datetime(year=2018, month=3, day=25, hour=23, minute=45)
```

**After**:

```python3
from beautiful_date import *

d = 25/Mar/2018
t = (25/Mar/2018)[23:45]
```

## Installation

```bash
pip install beautiful-date
```

## Examples

### Create Date

Using months names:

```python3
>>> from beautiful_date import *

>>> 25/Mar/2018 # European format
BeautifulDate(2018, 3, 25)
>>> Mar/25/2018 # US format
BeautifulDate(2018, 3, 25)
```

Using months numbers:

```python3
>>> 25/M[3]/2018 # European format
BeautifulDate(2018, 3, 25)
>>> M[3]/25/2018 # US format
BeautifulDate(2018, 3, 25)
```

Or alternatively:

```python3
>>> D @ 25/3/2018 # European format (default)
BeautifulDate(2018, 3, 25)

>>> D = MDY() # Add this at the top of your script to use US format.
>>> d = D @ 3/25/2018 # US format
BeautifulDate(2018, 3, 25)
```

You can also easily retrieve current date as a `BeautifulDate` object and current time using:

```python3
>>> D.today()
BeautifulDate(2020, 8, 24)

>>> D.now()
datetime.datetime(2020, 8, 24, 0, 59, 12, 451363)

>>> D.tomorrow()
BeautifulDate(2020, 8, 25)

>>> D.yesterday()
BeautifulDate(2020, 8, 23)
```

### Create Datetime

Previous methods create `BeautifulDate` objects which are inherited from `date` but can be
easily extended to `datetime` using indexing/slicing:

```python3
>>> (Oct/16/1995)[:]
datetime.datetime(1995, 10, 16, 0, 0)

>>> (Oct/16/1995)[23]
datetime.datetime(1995, 10, 16, 23, 0)

>>> (Oct/16/1995)[23:14]
datetime.datetime(1995, 10, 16, 23, 14)

>>> (Oct/16/1995)[23:14:10]
datetime.datetime(1995, 10, 16, 23, 14, 10)
```

You can also use prefix `D @` if you need months by their numbers:

```python3
>>> (D @ 16/10/1995)[:]
datetime.datetime(1995, 10, 16, 0, 0)

>>> (D @ 16/10/1995)[23]
datetime.datetime(1995, 10, 16, 23, 0)

>>> (D @ 16/10/1995)[23:14]
datetime.datetime(1995, 10, 16, 23, 14)

>>> (D @ 16/10/1995)[23:14:10]
datetime.datetime(1995, 10, 16, 23, 14, 10)
```

### Date/Datetime manipulations:

This library also provides simple interface for
[relativedelta](http://dateutil.readthedocs.io/en/stable/relativedelta.html) from
[dateutil](http://dateutil.readthedocs.io/en/stable/index.html)

Notice that singular time unit (year, month, ...) sets given value, plural (years, months,) adds it.

#### Shortcuts:

```python
>>> 5*days.from_today
BeautifulDate(2023, 9, 17)

>>> 1*hours.from_now
datetime.datetime(2023, 9, 12, 12, 53, 56)

>>> 3*days.since(15/Mar/2023)
BeautifulDate(2023, 3, 18)

>>> 5*days.until_today
BeautifulDate(2023, 9, 7)

>>> 1*hours.until_now
datetime.datetime(2023, 9, 12, 11, 13, 4)

>>> 3*days.until(15/Mar/2023)
BeautifulDate(2023, 3, 12)
```

#### Adding/Subtracting/Setting timedeltas:

```python3
>>> d = 26/Mar/2018
>>> t = d[12:23:15]

>>> d + 2 * years
BeautifulDate(2020, 3, 26)
>>> d - 2 * days
BeautifulDate(2018, 3, 24)

>>> t + 25 * hours
datetime.datetime(2018, 3, 27, 13, 23, 15)
```

Available deltas: `years`, `months`, `weeks`, `days`, `hours`, `minutes`,
`seconds`, `microseconds`, `leapdays`
(see [relativedelta](http://dateutil.readthedocs.io/en/stable/relativedelta.html)).

```python3
>>> d = 26/Mar/2018
>>> t = d[12:23:15]

>>> d + 2022 * year
BeautifulDate(2022, 3, 26)
>>> d += 2 * day
>>> d
BeautifulDate(2018, 3, 2)

>>> t + 22 * hour
datetime.datetime(2018, 3, 26, 22, 23, 15)
>>> t += 22 * hour
>>> t
datetime.datetime(2018, 3, 26, 22, 23, 15)
```

Available setters: `year`, `month`, `day`, `hour`, `minute`, `second`, `microsecond`,
`yearday` and `nlyearday`
(see [relativedelta](http://dateutil.readthedocs.io/en/stable/relativedelta.html)).

#### Weekdays:

Get next Monday:

```python3
>>> d = 29/Mar/2018 # Thursday
>>> d + MO # Equivalent to MO(1)
BeautifulDate(2018, 4, 2)
```

Get second to next Monday:

```python3
>>> d = 29/Mar/2018
>>> d + MO(2)
BeautifulDate(2018, 4, 9)
```

Get last Saturday:

```python3
>>> d = 29/Mar/2018
>>> d - SA
BeautifulDate(2018, 3, 24)
```

Get second to last Saturday:

```python3
>>> d = 29/Mar/2018
>>> d - SA(2)
BeautifulDate(2018, 3, 17)
```

Get second to last Saturday (same as previous):

```python3
>>> d = 29/Mar/2018
>>> d + SA(-2)
BeautifulDate(2018, 3, 17)
```

### Util

#### drange:

You can use `drange` to generate ranges of dates:

```python3
>>> for d in drange(27/Mar/1994, 5/Apr/1994):
... print(d)
1994-03-27
1994-03-28
1994-03-29
1994-03-30
1994-03-31
1994-04-01
1994-04-02
1994-04-03
1994-04-04

>>> for d in drange(27/Mar/1994, 5/Apr/1994, 2*days):
... print(d)
1994-03-27
1994-03-29
1994-03-31
1994-04-02
1994-04-04
```

and datetimes:

```python3
>>> for dt in drange((27/Mar/1994)[10:25], (4/Apr/1994)[10:10]):
... print(dt)
1994-03-27 10:25:00
1994-03-28 10:25:00
1994-03-29 10:25:00
1994-03-30 10:25:00
1994-03-31 10:25:00
1994-04-01 10:25:00
1994-04-02 10:25:00
1994-04-03 10:25:00

>>> for dt in drange((27/Mar/1994)[10:25], (4/Apr/1994)[10:10], 20*hours):
... print(dt)
1994-03-27 10:25:00
1994-03-28 06:25:00
1994-03-29 02:25:00
1994-03-29 22:25:00
1994-03-30 18:25:00
1994-03-31 14:25:00
1994-04-01 10:25:00
1994-04-02 06:25:00
1994-04-03 02:25:00
1994-04-03 22:25:00
```