https://github.com/mtlh/digits0ton

https://edabit.com/challenge/j9zed4GnykS48W6vh My solution to this problem in Python and JavaScript.
https://github.com/mtlh/digits0ton

algorithm coding-challenge javascript python

Last synced: 4 months ago
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https://edabit.com/challenge/j9zed4GnykS48W6vh My solution to this problem in Python and JavaScript.

• Host: GitHub
• URL: https://github.com/mtlh/digits0ton
• Owner: mtlh
• Created: 2020-08-24T09:27:28.000Z (over 5 years ago)
• Default Branch: master
• Last Pushed: 2020-08-24T09:30:40.000Z (over 5 years ago)
• Last Synced: 2025-01-03T04:47:06.744Z (11 months ago)
• Topics: algorithm, coding-challenge, javascript, python
• Homepage: https://edabit.com/challenge/j9zed4GnykS48W6vh
• Size: 1.95 KB
• Stars: 0
• Watchers: 1
• Forks: 0
• Open Issues: 0
• Metadata Files:
  • Readme: README.md

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README

          
# How Many Digits between 1 and N

https://edabit.com/challenge/j9zed4GnykS48W6vh My solution to this problem in Python and JavaScript.

## Python

def digits(number):

	number-=1

	n = 10**(len(str(number))-1)

	digits = 0

	while n>=1:

		digits+=(number-n+1)*len(str(number))

		number=n-1

		n//=10

	return digits

  

  ## JavaScript

  

  function digits(number) {

  if (typeof number === 'bigint') {

    return bigIntDigits(number)

  }

	let amountOfDigits = 0

  for (let i = 1; i <= number; i *= 10) {

    amountOfDigits += number - i

  }

  return amountOfDigits

}

function bigIntDigits(number) {

  const bigNumber = BigInt(number)

	let amountOfDigits = 0n

  for (let i = 1n; i <= bigNumber; i *= 10n) {

    amountOfDigits += bigNumber - i

  }

  return amountOfDigits

}