https://github.com/pwoolcoc/exmerl

Elixir wrapper for xmerl_*
https://github.com/pwoolcoc/exmerl

Last synced: about 1 month ago
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Elixir wrapper for xmerl_*

• Host: GitHub
• URL: https://github.com/pwoolcoc/exmerl
• Owner: pwoolcoc
• Created: 2014-05-13T20:52:10.000Z (over 10 years ago)
• Default Branch: master
• Last Pushed: 2017-01-23T15:07:02.000Z (almost 8 years ago)
• Last Synced: 2024-10-11T23:12:41.868Z (2 months ago)
• Language: Elixir
• Size: 10.7 KB
• Stars: 12
• Watchers: 3
• Forks: 2
• Open Issues: 1
• Metadata Files:
  • Readme: README.md

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README

        
# Exmerl

A wrapper for the xmerl\_\* suite of modules, though at the moment all

you can do is parse and use xpaths to select nodes.

## Usage

Currently it is possible to parse XML from a file or string using either `from_file/1,2`,

`from_string/1,2` or `parse/1,2`. They all accept an optional Keyword

list as the second argument. Possible options can be found in the erlang

documentation for the xmerl\_\* modules.

    iex(1)> # you can pass parse/1,2 a filename or an xml string

    iex(2)> Exmerl.parse("test.xml")

    {{:xmlElement, :root, :root, [], {:xmlNamespace,...

    ...

    ...

    iex(3)> {doc, rest} = Exmerl.from_string("""Test""")

    {{:xmlElement, :root, :root, [], {:xmlNamespace,...

    ...

    ...

You can traverse the document by using xpath selectors, and the

Exmerl.XPath.find function. `find/2,3,4,5` takes an XML document (or a

`{doc, rest}` pair as shown above), an xpath selector, and optional

`node`, `parent`, and a Keyword list of options. `find` will accept a

`{doc,rest}` pair to make it easier to pipe the output of `parse` into

`find`:

    iex(1)> Exmerl.parse("test.xml") |>

    ...(1)>   Exmerl.XPath.find("//some-node-name")

    {[{:xmlElement, ...

    ...

    ...

In this case, instead of returning `[result_term]`, it will return

`{[result_term], [rest]}`.