https://github.com/raviseta/count-sorted-vowel-strings
Leet code solution for count sorted vowel strings
https://github.com/raviseta/count-sorted-vowel-strings
Last synced: 9 months ago
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Leet code solution for count sorted vowel strings
- Host: GitHub
- URL: https://github.com/raviseta/count-sorted-vowel-strings
- Owner: raviseta
- Created: 2022-05-12T05:32:02.000Z (about 4 years ago)
- Default Branch: main
- Last Pushed: 2022-05-12T05:33:00.000Z (about 4 years ago)
- Last Synced: 2025-04-12T12:59:27.446Z (about 1 year ago)
- Language: Swift
- Size: 10.7 KB
- Stars: 0
- Watchers: 1
- Forks: 0
- Open Issues: 0
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Metadata Files:
- Readme: README.md
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README
# count-sorted-vowel-strings
Leet code solution for count sorted vowel strings
Given an integer n, return the number of strings of length n that consist only of vowels (a, e, i, o, u) and are lexicographically sorted.
A string s is lexicographically sorted if for all valid i, s[i] is the same as or comes before s[i+1] in the alphabet.
Example 1:
Input: n = 1
Output: 5
Explanation: The 5 sorted strings that consist of vowels only are ["a","e","i","o","u"].
Example 2:
Input: n = 2
Output: 15
Explanation: The 15 sorted strings that consist of vowels only are
["aa","ae","ai","ao","au","ee","ei","eo","eu","ii","io","iu","oo","ou","uu"].
Note that "ea" is not a valid string since 'e' comes after 'a' in the alphabet.
Example 3:
Input: n = 33
Output: 66045