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https://github.com/valentinefernandes/mysql-assignment
This repository consists of sql queries based on Employee database.
https://github.com/valentinefernandes/mysql-assignment
assignment database mysql mysql-queries sql
Last synced: 7 days ago
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This repository consists of sql queries based on Employee database.
- Host: GitHub
- URL: https://github.com/valentinefernandes/mysql-assignment
- Owner: ValentineFernandes
- License: mit
- Created: 2022-10-10T13:59:53.000Z (about 2 years ago)
- Default Branch: main
- Last Pushed: 2022-10-11T06:31:00.000Z (about 2 years ago)
- Last Synced: 2023-03-10T05:11:44.962Z (over 1 year ago)
- Topics: assignment, database, mysql, mysql-queries, sql
- Homepage:
- Size: 7.81 KB
- Stars: 9
- Watchers: 0
- Forks: 1
- Open Issues: 1
-
Metadata Files:
- Readme: README.md
- License: LICENSE
Awesome Lists containing this project
README
MYSQL ASSIGNMENT
# CREATE DATABASE
```javascript
CREATE DATABASE testdb;
```
# SHOW EXISTING DATABASE
```javascript
SHOW CREATE DATABASE testdb;
```
# USE COMMAND
```javascript
USE testdb;
```
# CREATE TABLE EMPLOYEE
```javascript
CREATE TABLE Employee
(
EmployeeID int,
FirstName varchar(255),
LastName varchar(255),
Email varchar(255),
AddressLine varchar(255),
City varchar(255)
);
```
# INSERT RECORDS IN EMPLOYEE TABLE
```javascript
INSERT INTO Employee (EmployeeID, FirstName, LastName, Email, AddressLine, City)
VALUES ('101', 'Lucas', 'Santos', '[email protected]', 'Brazil', 'Sao Paulo'),
('102', 'Carlos', 'Santiago', '[email protected]', 'Argentina', 'Buenos Aires'),
('103', 'Emanuel', 'DaSilva', '[email protected]', 'Brazil', 'Rio Grande do Sul'),
('104', 'Abril', 'Rodriguez', '[email protected]', 'Argentina', 'Mendoza'),
('105', 'Carolina', 'Bentresca', '[email protected]', 'Chile', 'Concepsion'),
('106', 'Carol', 'Santos', '[email protected]', 'Chile', 'Santiago'),
('107', 'Gabriela', 'Lopez', '[email protected]', 'Brazil', 'Amazonas'),
('108', 'Michael', 'DeCarvalho', '[email protected]', 'Brazil', 'Fortaleza'),
('109', 'George', 'Spencer', '[email protected]', 'United Kingdom', 'London'),
('110', 'Christina', 'Diemert', '[email protected]', 'United States', 'California');
```
# QUERIES
1. From the following table return complete information about the employees.
```javascript
SELECT * FROM Employee;
```
2. From the following table, write a SQL query to find the cities of all employees. Return city.
```javascript
SELECT City FROM Employee;
```
3. From the following table, write a SQL query to find the unique addressline of the employees. Return addressline.
```javascript
SELECT DISTINCT AddressLine
FROM Employee;
```
4. From the following table, write a SQL query to return EmployeeID, FirstName, LastName, City and AddressLine.
```javascript
SELECT EmployeeID,
FirstName,
LastName,
City,
AddressLine
FROM Employee;
```
5. From the following table, write a SQL query to count the number of characters except the spaces for each FirstName. Return FirstName length.
```javascript
SELECT length(trim(FirstName))
FROM Employee;
```
6. From the following table, write a SQL query to count the number of characters except the spaces for each LastName. Return LastName length.
```javascript
SELECT length(trim(LastName))
FROM Employee;
```
7. From the following table, write a SQL query to find the EmployeeID, FirstName, Email of all the employees.
```javascript
SELECT EmployeeID,
FirstName,
Email
FROM Employee;
```
8. From the following table, write a SQL query to find the unique AddressLine with LastName. Return AddressLine and LastName.
```javascript
SELECT DISTINCT AddressLine, LastName
FROM Employee;
```
9. From the following table, write a SQL query to find those employees who do not belong to AddressLine Brazil. Return complete information about the employees.
```javascript
SELECT *
FROM Employee
WHERE AddressLine NOT IN ('Brazil');
```
10. From the following table, write a SQL query to find those employees who do not belong to AddressLine Argentina. Return complete information about the employees.
```javascript
SELECT *
FROM Employee
WHERE AddressLine NOT IN ('Argentina');
```
11. From the following table, write a SQL query to find those employees who EmployeeID's are before 105. Return complete information about the employees.
```javascript
SELECT *
FROM Employee
WHERE EmployeeID<('105');
```
12. From the following table, write a SQL query to find those employees who EmployeeID's are after 105. Return complete information about the employees.
```javascript
SELECT *
FROM Employee
WHERE EmployeeID>('105');
```
13. From the following table, write a SQL query to find those employees who EmployeeID's are before or equal to 105. Return complete information about the employees.
```javascript
SELECT *
FROM Employee
WHERE EmployeeID<=('105');
```
14. From the following table, write a SQL query to find those employees who EmployeeID's are after or equal to 105. Return complete information about the employees.
```javascript
SELECT *
FROM Employee
WHERE EmployeeID>=('105');
```
15. From the following table, write a SQL query to find those employees who EmployeeID is equal to 105. Return complete information about the employees.
```javascript
SELECT *
FROM Employee
WHERE EmployeeID=('105');
```
16. From the following table, write a SQL query to find the details of the employee ‘Carol’.
```javascript
SELECT *
FROM Employee
WHERE FirstName = 'Carol';
```
17. From the following table, write a SQL query to find the FirstName of the employees whose length is six. Return employee FirstName.
```javascript
SELECT FirstName
FROM Employee
WHERE length(FirstName)=6;
```
18. From the following table, write a SQL query to find the details of the employee LastName ‘Santos’.
```javascript
SELECT *
FROM Employee
WHERE LastName = 'Santos';
```
19. From the following table, write a SQL query to find those employees whose AddressLine is ‘Brazil’. Return complete information about the employees.
```javascript
SELECT *
FROM Employee
WHERE AddressLine = 'Brazil';
```
20. From the following table, write a SQL query to find those employees whose AddressLine is ‘Argentina’. Return complete information about the employees.
```javascript
SELECT *
FROM Employee
WHERE AddressLine = 'Argentina';
```
21. From the following table, write a SQL query to find those employees whose AddressLine are either Brazil or Argentina. Return complete information about the employees.
```javascript
SELECT *
FROM Employee
WHERE AddressLine IN ('Brazil','Argentina');
```
22. From the following table, write a SQL query to find those employees whose AddressLine are either Chile or United States. Return complete information about the employees.
```javascript
SELECT *
FROM Employee
WHERE AddressLine IN ('Chile','United States');
```
23. From the following table, write a SQL query to find those employees whose AddressLine begin's with C. Return complete information about the employees.
```javascript
SELECT *
FROM Employee
WHERE AddressLine LIKE 'C%';
```
24. From the following table, write a SQL query to find those employees whose AddressLine ends with l. Return complete information about the employees.
```javascript
SELECT *
FROM Employee
WHERE AddressLine LIKE '%l';
```
25. From the following table, write a SQL query to find those employees whose AddressLine values with 'rg' in between. Return complete information about the employees.
```javascript
SELECT *
FROM Employee
WHERE AddressLine LIKE '%rg%';
```
# LICENSE
This assignment is under MIT license.