https://github.com/vsouza/graphql-handler

GraphQL Handler with Swift Perfect Framework
https://github.com/vsouza/graphql-handler

graphql graphql-handler handler linux perfect server-side swift

Last synced: 2 days ago
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GraphQL Handler with Swift Perfect Framework

• Host: GitHub
• URL: https://github.com/vsouza/graphql-handler
• Owner: vsouza
• License: mit
• Created: 2017-02-08T16:18:44.000Z (almost 8 years ago)
• Default Branch: master
• Last Pushed: 2018-11-01T02:14:39.000Z (about 6 years ago)
• Last Synced: 2024-04-13T21:19:47.426Z (7 months ago)
• Topics: graphql, graphql-handler, handler, linux, perfect, server-side, swift
• Language: Swift
• Homepage:
• Size: 10.7 KB
• Stars: 21
• Watchers: 5
• Forks: 1
• Open Issues: 0
• Metadata Files:
  • Readme: README.md
  • License: LICENSE

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README

        
# GraphQL Handler

> Swift GraphQL Handler

[![Swift Version][swift-image]][swift-url]

[![License][license-image]][license-url]

[![codebeat badge](https://codebeat.co/badges/1c0f9ac0-84e2-4c1d-96ef-5c0094bca263)](https://codebeat.co/projects/github-com-vsouza-graphql-handler-master)

A simple handler implementation of GraphQL using [Perfect](http://perfect.org)

## How it works?

A simple route with a `indexHandler` call when `GET` on `/graphql` route.

```swift

routes.add(method: .get, uri: "/graphql", handler: indexHandler)

```

Define your schema with `RootQueries`, `RootMutations`, `CustomTypes` e etc...

```swift

let UserType =  try! GraphQLObjectType(

    name: "User",

    description: "A user in system",

    fields:[

        "id": GraphQLField(

            type: GraphQLNonNull(GraphQLString),

            description: "The id of the user."

        ),

        "name": GraphQLField(

            type: GraphQLString,

            description: "The name of the user."

        ),

        "email": GraphQLField(

            type: GraphQLString,

            description: "The email of the user."

        ),

    ]

)

```

In handler you will call the GraphQL parser:

```swift

let result = try graphql(schema: schema, request: query)

```

__[GraphQL library](https://github.com/GraphQLSwift/GraphQL)__ returns a `map`

by default, to get a JSON you should use `result.description` like @paulofaria

says here:

[#1](https://github.com/GraphQLSwift/GraphQL/issues/1#issuecomment-257182572)

## Usage example

`make run`

listen on `:8080`

`http://localhost:8080/graphql?query=query{user(id: "3000"){id,name,email}}`

## Release History

* 0.0.2

    * Improve Schema and add sample data

* 0.0.1

    * Simple handler with basic schema

## Meta

Vinicius Souza – [@iamvsouza](https://twitter.com/iamvsouza) – [email protected]

Distributed under the MIT license. See [License](http://vsouza.mit-license.org/)

[https://github.com/vsouza](https://github.com/vsouza/)

[swift-image]:https://img.shields.io/badge/swift-4.0-orange.svg

[swift-url]: https://swift.org/

[license-image]: https://img.shields.io/badge/License-MIT-blue.svg

[license-url]: LICENSE