https://github.com/yankouskia/advanced-zeros
Let's count zeros!
https://github.com/yankouskia/advanced-zeros
Last synced: 19 days ago
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Let's count zeros!
- Host: GitHub
- URL: https://github.com/yankouskia/advanced-zeros
- Owner: yankouskia
- License: mit
- Created: 2018-02-19T08:49:49.000Z (about 7 years ago)
- Default Branch: master
- Last Pushed: 2018-03-12T20:41:12.000Z (about 7 years ago)
- Last Synced: 2025-03-29T14:12:10.278Z (26 days ago)
- Language: JavaScript
- Size: 8.79 KB
- Stars: 11
- Watchers: 2
- Forks: 706
- Open Issues: 1
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Metadata Files:
- Readme: README.md
- License: LICENSE
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README
# advanced-zeros
Let's count zeros!## Task
Your task is to implement `getZerosCount` function, which takes any integer number `number` (`1 <= number <= 10^7`) as first argument and any integer number `base` (`2 <= base <= 256`) as second argument. You should calculate *how many zeros in the end of number, which is factorial of `number` in `base` base system*
For example:
```js
const zerosCount = getZerosCount(10, 10); // Factorial of 10 is 3628800 and the same in 10th base system
console.log(zerosCount); // 2. Because there is 2 *tail* zeros in number 3628800
``````js
const zerosCount = getZerosCount(16, 16); // Factorial of 16 is 20922789888000 in 10th base system and *130777758000* in 16th base system
console.log(zerosCount); // 3. Because there is 3 *tail* zeros in number *130777758000*
```### Important!
Do not try to calculate factorial! First - you will not get exact answer on big numbers. Second - it could take several years to calculate factorial on big integers! Try to think up your awesome solution without such calculations. Good luck!